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Question 16
Mu
Riemann Sums
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Question
Evaluate
lim
n
→
∞
∑
k
=
1
n
1
4
n
2
−
k
2
\displaystyle\lim_{n\to\infty}\sum_{k=1}^{n}\frac1{\sqrt{4n^2-k^2}}
n
→
∞
lim
k
=
1
∑
n
4
n
2
−
k
2
1
.
A.
π
2
\frac\pi2
2
π
B.
π
3
\frac\pi3
3
π
C.
π
4
\frac\pi4
4
π
D.
π
6
\frac\pi6
6
π
E.
NOTA
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