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Question 18
Mu
Definite Integral
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Question
The value of
∫
0
1
x
3
x
4
+
1
d
x
\displaystyle\int_0^1\frac{x^3}{\sqrt{x^4+1}}\,dx
∫
0
1
x
4
+
1
x
3
d
x
is a root of
y
=
4
x
2
+
4
x
+
K
y=4x^2+4x+K
y
=
4
x
2
+
4
x
+
K
. Find
K
K
K
.
A.
−1
B.
0
C.
1
D.
2
E.
NOTA
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